I am attaching in the PDF file my model. The problem as usual is on the finding of Steady State. As you can see in my file, the steady state system I could solve it on its own. That is, I already managed to solve separately from the dynamic block the SS system of equations. The problem arises when I want to simulate the dynamic model. In all cases, the usual error is that dynare cannot find/compute the steady state.

I tried 4 different methods.

[ul]1. Using the computed values of the steady state as initial guesses
2. Using the steady_state_model block
3.Using the [Dynamic] [Static] tags
4. I let dynare to call the particular steady state function i.e calling filename_steady_state.m [/ul]

In all cases there was a failure to compute the steady state. Your help will be much appreciated model.pdf (118 KB) dynare_model.mod (3 KB)

The steady state model-block is only for perfectly accurate steady states. Otherwise, you must use the initval-block. Using the initval block with your file results in the message

[quote]Error using print_info (line 90)
The solution to the static equations is not a steady state of the dynamic model: verify that the equations tagged by [static] and [dynamic] are consistent
[/quote]

Thus, there is something wrong with your [static] equations (or the dynamic ones for this purpose)

Thank you for your reply. The code, is just a sample from the different methods I used to simulate the model. As I said, I could individually compute the steady state. For instance, I have attached the relevant mod file that does this and it perfectly works. So, the static model is correctly specified. My big mystery is why dynare cannot compute it in my first file, even if I particularly instruct dynare to solve a particular static model, as for instance with [static] tags or with the steady_state_model block. So Either cannot understand what dynare does or I am missing something. dynare_model.mod (2.75 KB) steadystate_code.mod (1.07 KB)

You need to fix the mistakes in your model setup. If

A=(1-rho)*Abar+ rho*A(-1)+e;
then the steady state of A is Abar. But you say:

steady_state_model;
kh=0.640833; % ==> The value was computed once I solved the system seperately
theta=1/(1+kh);
A=log(Abar);
Moreover, you did not set sigmat and exr. Put

before steady and first try to make the residuals of the last 2 equations 0.

I modified the model, according to the attached code but again does not work. Actually, I do not how I could eliminate the remaining residuals which are non zero. I manage to eliminate those for most of the equations but not for two of them.
Even worst, I receive an error message that says

With the unstable version I am able to run your attached file without the mentioned error message.

Please be more careful in your mod-file. The problematic equations are

rk=exp(A)*alpha*kh^(alpha-1);
rh=exp(A)*(1-alpha)*kh^(alpha);
Note the exp(A).
In the steady_state_model block you are saying

rk=A*alpha*kh^(alpha-1);
rh=A*(1-alpha)*kh^(alpha);
Note that there is only A. This cannot work.

In addition:

[dynamic] sigmat=sigma*(1-z*ln(A))^2;
[static] sigmat=sigma;
Neither z is 0 in steady state nor is ln(A). How then can sigma then be the steady state of sigmat? Clearly, the static equation does not match the dynamic one.