Log-linearization Euler equation

Hi everyone,
Could anyone help me with this detailed derivation of Euler equation?

I’m not sure Log-linearizing of the following equation (1):

Screen Shot 2023-01-05 at 1.25.46 PM

equal equation (2)
Screen Shot 2023-01-05 at 1.26.11 PM

or equation (3)
Screen Shot 2023-01-05 at 1.26.25 PM

Thanks.

The relevant part is the Taylor approximation of \frac{1}{1+i} with respect to i, which is -\frac{1}{(1+i)^2}(i_t- i)=-\frac{i}{(1+i)^2}\frac{i_t-i}{i}=-\frac{i}{(1+i)^2}\hat i_t. After canceling the \frac{1}{1+i} term present in all terms of the equation, you are left with -\frac{i}{1+i}\hat i_t, which corresponds to (3).
You should get (2) if you are not interested in percentage deviations of the net interest rate i_t from its steady state, but of the gross interest rate 1+i_t from its steady state. But you did not explain the notation.

Hi Prof,
Thank you for your detailed explanation. In my question, i is the net interest rate. That’s why I’m so confused. If I care about the percentage deviations of the gross interest rate from its steady state. I should get the following equation, right?

Yes, indeed, but 1+i\approx 1, so the percentage deviation of the gross interest rate from its steady state is often approximated by the net interest rate deviation.

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