# Model consistent paths to the steady-state

**URL:** <https://forum.dynare.org/t/model-consistent-paths-to-the-steady-state/26261>\
**Category:** Perfect foresight simulations\
**Created:** [14 August 2024 13:08 UTC](https://forum.dynare.org/t/model-consistent-paths-to-the-steady-state/26261 "2024-08-14T13:08:05Z")\
**Posts on this page:** 1\
**Showing post:** 4

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**Author:** ![jpfeifer](https://forum.dynare.org/user_avatar/forum.dynare.org/jpfeifer/32/5044_2.png) [@jpfeifer](https://forum.dynare.org/u/jpfeifer)\
**Post date:** [14 August 2024 15:15 UTC](https://forum.dynare.org/t/model-consistent-paths-to-the-steady-state/26261/4 "2024-08-14T15:15:58Z")

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1. In that case, the terminal condition will only indirectly matter for \pi\_t^4 via its effect on \pi\_t.
2. Yes, that is the point of `endval`. However, terminal conditions usually only make sense if you have a steady state as the terminal condition.
3. Yes, the mathematical two boundary problem is still well-defined. The economic problem often is not, because the terminal condition of being in steady state will be incorrect if there is insufficient time for the problem to settle back to steady state. You can often see this issue by abrupt jumps in the last period, which are fine mathematically but not economically.

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